Fabric Technology - Mini Project Report
This mini project was prepared to fulfill requirement of fabric technology subject at the open university of Sri Lanka, Nawala, Nugegoda
Author: K.K.T Madhusanka (My Answer)
Warp count in tex
Description
In
warp count find linear density of warp direction of fabric and warp count
commonly calculated in to tex and it means how many grams in 1000 m length of
yarn.
Methodology
-
Firstly 20 cm length of warp direction
based five samples were cut diagonally using 20 cm template.
-
Next, one yarn was removed each five
samples.
-
Next, each yarn was unprimed using crimp
tester individually and uncrimped length was recorded.
-
Then, weights of each uncrimped yarn
specimen were recorded individually.
-
Finally all details were distributed and
Tex value was calculated.
Calculation
Sample No:
|
Length
|
Uncrimped length
|
Uncrimped length (m)
|
Weight
|
1
|
20 cm
|
20.2 cm
|
0.202 m
|
0.0069 g
|
2
|
20 cm
|
20.3 cm
|
0.203 m
|
0.0066 g
|
3
|
20 cm
|
20.2 cm
|
0.202 m
|
0.0055 g
|
4
|
20 cm
|
20.1cm
|
0.201 m
|
0.0068 g
|
5
|
20 cm
|
20.1cm
|
0.201 m
|
0.0055 g
|
Average
|
20.18 cm
|
0.2018 m
|
0.00626 g
|
Sample
No: 01
In
20.2 cm uncrimped length’s weight = 0.0069 g
For
1000 m weight = (0.0069 g/ 20.2 x 10-2m) x 1000
m
= 34.15841584 g
= 34.16 Tex
Sample
No: 02
In
20.3 cm uncrimped length’s weight = 0.0066 g
For
1000 m weight = (0.0066 g/ 20.3 x 10-2m) x 1000 m
= 32.51231527g
= 32.50 Tex
Sample
No: 03
In
20.2 cm uncrimped length’s weight = 0.0055 g
For
1000 m weight = (0.0055 g/ 20.2 x 10-2m)
x 1000 m
= 27.22772277g
= 27.23 Tex
Sample
No: 04
In
20.1 cm uncrimped length’s weight = 0.0068 g
For
1000 m weight = (0.0068 g/ 20.1 x 10-2m)
x 1000 m
= 33.83084577g
= 33.90 Tex
Sample
No: 05
In
20.1 cm uncrimped length’s weight = 0.0055 g
For
1000 m weight = (0.0055 g/ 20.1 x 10-2m)
x 1000 m
= 27.36318408g
= 27.40 Tex
Average
Tex value = (34.16 Tex + 32.50 Tex +
27.23 Tex + 33.90 Tex + 27.40 Tex)/5
= 31.038 Tex
Observations
·
When uncrimping yarns small length of
yarn was increased.
·
Increased uncrimped length was little
bit difference on each five specimen yarn.
·
When weight test of uncrimped yarns
individually, small weight difference of each yarn specimen was found.
Conclusion
·
Each place of fabric had small thick and
thin places of warp direction shown small warp count in Tex value (little bit)
of each test specimen hence, can conclude this fabric has small Tex variation
at several places of fabric.
·
Tex variation were little bit amount
hence, can be concluded this fabric has good and acceptable warp count in each
area and this is good fabric and suitable for clothing manufacturing process.
(ii)
Weft count in tex
Description
In
weft count find linear density of weft direction of fabric and weft count
commonly calculated in to tex and it means how many grams in 1000 m length of
yarn.
Methodology
-
Firstly 20 cm length of weft direction
based five samples were cut diagonally using 20 cm template.
-
Next, one yarn was removed each five
samples.
-
Next, each yarn was unprimed using crimp
tester individually and uncrimped length was recorded.
-
Then, weights of each uncrimped yarn
specimen were recorded individually.
-
Finally all details were distributed and
Tex value was calculated.
Calculation
Sample No:
|
Length
|
Uncrimped length
|
Uncrimped length (m)
|
Weight
|
1
|
20 cm
|
20.4 cm
|
0.205 m
|
0.0062 g
|
2
|
20 cm
|
20.5 cm
|
0.205 m
|
0.0058 g
|
3
|
20 cm
|
20.4 cm
|
0.204 m
|
0.0059 g
|
4
|
20 cm
|
20.2 cm
|
0.202 m
|
0.0053 g
|
5
|
20 cm
|
20.4 cm
|
0.204 m
|
0.0054 g
|
Average
|
20.38 cm
|
0.2038 m
|
0.00572 g
|
Sample
No: 01
In
20.4 cm uncrimped length’s weight = 0.0062 g
For
1000 m weight = (0.0062 g/ 20.4 x 10-2m) x 1000
m
= 30.39215686 g
= 30.40 Tex
Sample
No: 02
In
20.5 cm uncrimped length’s weight = 0.0058 g
For
1000 m weight = (0.0058 g/ 20.5 x 10-2m)
x 1000 m
= 28.29268293g
= 28.30 Tex
Sample
No: 03
In
20.4 cm uncrimped length’s weight = 0.0059 g
For
1000 m weight = (0.0059 g/ 20.4 x 10-2m)
x 1000 m
= 28.92156863g
= 28.92 Tex
Sample
No: 04
In
20.2 cm uncrimped length’s weight = 0.0053 g
For
1000 m weight = (0.0053 g/ 20.2 x 10-2m)
x 1000 m
= 26.23762376g
= 26.24 Tex
Sample
No: 05
In
20.4 cm uncrimped length’s weight = 0.0054 g
For
1000 m weight = (0.0054 g/ 20.4 x 10-2m)
x 1000 m
= 26.47058824g
= 26.50 Tex
Average
Tex value = (30.40
Tex + 28.30
Tex + 28.92
Tex + 26.24 Tex + 26.50
Tex)/5
= 28.072 Tex
Observations
·
When uncrimping yarns, small length of
yarn was increased.
·
Uncrimp length of weft yarns were bit
higher than warp yarns uncrimp lengths.
·
Increased uncrimped length was little
bit difference on each five specimen yarn.
·
When weight test of uncrimped yarns
individually, small weight difference of each yarn specimen was found.
Conclusion
·
Weft yarn had higher crimp than warp
yarn.
·
Each place of fabric had small thick and
thin places of weft direction shown small weft count in Tex value (little bit)
of each test specimen hence, can conclude this fabric has small Tex variation
at several places of fabric.
·
Tex variation were little bit amount
hence, can be concluded this fabric has good and acceptable weft count in each
area and this is good fabric and suitable for clothing manufacturing process.
(iii)
Warp density
Description
In
warp density count, find how many ends/ yarns available in one square inch or
square centimeter of warp direction of fabric.
Methodology
-
2 x 2 cm counting glass was kept on
fabric.
-
Simple pen marks were kept on each nook
inside of counting glass covered fabric area connected them for correct reading
-
Next counting lens was focused with eye
and counted number of warp yarns in square area using needle.
-
Finally warp density was converted in to
one centimeter and inch (1 inch = 2.54 cm).
Calculation
Sample No
|
Warp Density in 2 cm
|
Warp Density in 1 cm
|
Fixed for 1cm
|
1
|
45
|
22.5
|
22
|
2
|
46
|
23
|
23
|
3
|
45
|
22.5
|
22
|
4
|
45
|
22.5
|
22
|
5
|
46
|
23
|
23
|
Average
|
45.4
|
22.7
|
22
|
Here
final warp density value was selected as averaged values without decimal points
hence,
Warp
density in 1 square centimeter = 22
Warp
density in 1 inch = 22.7 x 2.54
=
57.658
Hence
taken as, less val = 57
Observations
·
·
When warp density counting, of five
places found different number of yarn values.
·
When averaging such value decimal points
were not taken as density count and fix number was taken.
·
Warp yarn density has high value than
weft density
Conclusion
·
Warp beam arranging with weaving
preparatory process, some warp yarn had arranged with small gap and sometime
when weaving small unbalance had been occurred in some places.
·
Weaving preparatory process, arrange higher
number of warp yarns on warp beam to get optimum strength.
(iv)
Weft density
Description
In
weft density count, find how many picks/ yarns available in one square inch or
square centimeter of weft direction of fabric.
Methodology
-
2 x 2 cm counting glass was kept on
fabric.
-
Simple pen marks were kept on each nook
inside of counting glass covered fabric area connected them for correct reading
-
Next counting lens was focused with eye
and counted number of weft yarns in square area using needle.
-
Finally weft density was converted in to
one centimeter and inch (1 inch = 2.54 cm).
Calculation
Sample No
|
Weft Density in 2 cm
|
Weft Density in 1 cm
|
Fixed for 1cm
|
1
|
43
|
21.5
|
21
|
2
|
44
|
22
|
22
|
3
|
42
|
21
|
21
|
4
|
42
|
21
|
21
|
5
|
43
|
21.5
|
21
|
Average
|
42.8
|
21.4
|
21.2 (21)
|
Here
final weft density value was selected as averaged values without decimal points
hence,
Weft
density in 1 square centimeter = 21
Warp
density in 1 inch = 21 x 2.54
= 53.34
Hence
taken as, less val = 53
Observations
·
·
When weft density counting, of five
places found different number of yarn values.
·
When averaging such value decimal points
were not taken as density count and fix number was taken.
Conclusion
·
When weaving process weft yarn goes
around warp yarns hence high crimp and little unbalance had been occurred.
·
This fabric’s warp and weft density
count different number of yarn value had small gap hence, can be conclude this
fabric had good ends per inch and picks per inch value and suitable for
clothing manufacturing process.
(v) Cloth cover factor
Description
In
warp density count, find how many ends/ yarns available in one square inch of
warp direction of fabric and to find warp cover factor, warp density divided by
square root of warp yarn’s cotton count. In weft density count, find how many
picks/ yarns available in one square inch of warp direction of fabric. And to
find weft cover factor, weft density divided by square root of weft yarn’s cotton
count.
Cloth cover factor = Warp cover factor (k1) + Weft
cover factor (k2)
Methodology
-
Firstly, warp density (per cm) was
converted in to ends per inch (1 inch = 2.54 cm).
-
Warp count in Tex was converted in to
cotton count (Tex x Ne = 590.5).
-
To find warp cover factor (k1)
warp density was divided by square root of cotton (Ne) count.
-
Next, weft density (per cm) was
converted in to picks per inch (1 inch = 2.54 cm).
-
Weft count in Tex was converted in to
cotton count (Tex x Ne = 590.5).
-
To find weft cover factor (k2)
weft density was divided by square root of cotton (Ne) count.
-
Finally by adding total value of k1 and
k2, cloth cover factor was calculated.
-
Calculation
Warp
density = 57.658 /inch
Ne
value of warp = 590.5/Tex
= 590.5/31.038
= 19.02506 Ne
Warp
cover factor (k1) = Warp density/√Ne
= 57.658/√19.02506
= 13.2189
Weft
density = 53.34 /inch
Ne
value of weft = 590.5/Tex
= 590.5/28.072
= 21.0351952
Ne
Weft
cover factor (k2) = Weft density/√Ne
= 53.34/√21.0351952
= 12.4280097
= 11.63000
Cloth cover factor =
Warp cover factor (k1) + Weft cover factor (k2)
= 13.2189 + 11.63000
= 25.4976233
= 24.849
Observations
·
·
Cloth cover factor depend on yarn count
·
Cloth cover factor depend on number of
yarn in square inch.
·
Warp area found little high cover factor
than weft
Conclusion
·
Cloth cover factor is combination of
weft and warp cover factor
·
Cloth cover factor depending on warp and
weft density
·
Cloth cover factor depending on linear
density of weft and warp yarn.
(vi) GSM Test
Description
G.S.M
means grams per square meter and it means areal density of particular fabric.
If higher weight available in square meter, considered as higher GSM based
fabric and higher area density. If low weight available in square meter,
considered as low GSM based fabric and low area density it means light weight
fabric.
Methodology
-
Firstly, five samples were cut using
100cm2 area based G.S.M cutter.
-
Next, each specimen weight was measured
individually.
-
Finally each sample’s mass divided by
area.
Calculation
Sample No
|
Weight
|
GSM by multiplying 100
|
1
|
1.1562
|
115.62
|
2
|
1.1741
|
117.41
|
3
|
1.1589
|
115.89
|
4
|
1.1511
|
115.11
|
5
|
1.1479
|
114.79
|
Average
|
1.15764
|
115.764
|
Here
original calculation can be written as for averaged weight,
= Grams/ Square meter
Here
1.15764 averaged weight was found in 100 square centimeter hence, need to find
real weight for one square meter.
= (1.15764g/100 x 10-4 m2)
= (1.15764g/1x 10-2m2)
It can be written as, = (1.15764g x 100 m-2)
GSM = 115.764 gm-2
Observations
·
·
Little bit different gram values and G.S.M
value found in cut samples
·
Near to selvedge place was seen bit high
GSM value than middle of fabric area based samples.
Conclusion
·
Some area of fabric has thick and thin
yarn based places change linear density of yarns and grams per square meter
(GSM) value.
·
According to tightly parallel yarn
packing of nearest area of selvedge have bit higher grams per square meter
value than middle of fabric.
(vii) Colour (by visual
inspection)
Description
Colour
of fabric is essential part of fabric. Different colours, repeats, designs
based of fabrics are used in textile and apparel industry to get consumer
attraction. And in laboratory test basically colour check visually as well as
using machinery just like L*a*b* values. Apart this, colour fastness properties
due to external resources just like light, abrasion, washing, perspiration, etc
are considered. Simply colour of fabric can be explained when sun light falling
in to fabric, certain amount of wave length of white light is absorbed by fabric
and other waves are reflected. This reflected wave complex give sensation to
human eye is identified as fabric colour.
Methodology &
Colour Assessment
-
Several places of plain woven fabric were
visually inspected and roughly colour is identified as somewhat light yellow
colour.
-
Several places of plain knitted fabric
were visually inspected and roughly colour assessed as off white.
Observations
·
·
Colour was roughly assessed without
using assessing tools and equipment
·
For assessing colour using eye counting
glass lens was used to identify dark spots.
Conclusion
·
Dark spots of plain woven grey fabric
may size coat particles or foreign materials.
·
Knitted fabric has small colour shade on
off white area and concludes as dust or foreign materials on some area of
fabric.
·
This is only rough assessment and to get
accuracy of colour it is essential to use colour assessing procedure just like
L,A,B or other colour evaluation and distribution method.
(viii) Tensile Strength
in Warp and Weft Directions
Description
In
tensile test resistance of the particular fabric sample against perpendicular
tensile force applied on it, is considered and in this test each five samples
of warp and weft specimens are used. In grab method measures effective strength
and in strip method strength with parallel yarns is measured.
Methodology
-
There were five warp and five weft
samples cut according to the given template to met length 20 cm.
-
Before cutting warp direction were
marked by arrow.
-
Next, both of width sides of cut
specimen were fayed 0.5 cm.
-
Next, tensile strength tester was switch
on and software was run.
-
Next, testing procedure was selected
using software. (Eg: AATCC, ISO, etc.)
-
Next machine settings were applied just
like gauge length, load cell, extension mm, etc.
-
After, selected weft or warp option
button of software.
-
In after specimen was clamped on machine.
-
Next,
force was adjusted “0”
-
Next, pre pressure added.
-
Then, using test specimen command button
of software, test was launched.
-
Finally load elongation curve based
results were recorded.
Calculations/ Recordings\
Sample
|
Warp
|
Weft
|
||
Breaking Force
|
Elongation
|
Breaking Force
|
Elongation
|
|
1
|
235 N
|
18.75 mm
|
217.8 N
|
16.94 mm
|
2
|
236 N
|
17.68 mm
|
142.1 N
|
17.26 mm
|
3
|
232.3 N
|
17.6 mm
|
160.6 N
|
18.32 mm
|
4
|
234.5 N
|
17.84 mm
|
150.6 N
|
16.72 mm
|
5
|
192.6 N
|
16.36 mm
|
151.4 N
|
17.24 mm
|
Average
|
226.08 N
|
17.646 mm
|
164.5 N
|
17.296 mm
|
Observations
·
In warp specimen’s tensile test found
higher breaking force ratio to comparison its elongation values.
·
In weft specimen’s tensile test found
higher elongation ratio to comparison its breaking force.
·
Warp specimens tensile strength were
higher than warp specimens tensile strength.
·
Conclusion
·
Weaving preparatory process in warp beam
arrangement use highly twisted, strength and size coated yarns gives higher
strength and low elongation of warp direction fabric.
·
Weft warns goes around warp yarns and
creates higher crimp hence, when tensile load high crimp try to uncrimp then
conclude weft direction has higher elongation ratio by comparison to its
tensile strength.
PART 02:
Calculations for Weft Knitted Fabrics
Course per cm
Description
In
this practical test count how many courses available in one centimeter.
Methodology
-
First knitted fabric was spread on table
without stretching.
-
Counting glass was kept on knitted
fabric.
-
Eye focused on counting glass lens.
-
Counting process was started using sharp
pointed needle or rod.
-
This counting process was done widthwise
of fabric and repeated on five places.
-
Finally each result was recorded.
Calculations/
Recordings
Place
|
No. of course
per 2cm
|
No. of course per 1cm
|
course per inch
|
1
|
35
|
17.5
|
44.45
|
2
|
35
|
17.5
|
44.45
|
3
|
35
|
17.5
|
44.45
|
4
|
35
|
17.5
|
44.45
|
5
|
35
|
17.5
|
44.45
|
Average
|
35
|
17.5/cm
|
44.45/inch
|
Here
each observation were taken using 2cm x 2cm
hence, finally 17.5 average was found but courses count should not
decimal points based hence courses/cm value is concluded as 18.
Observations
·
When counting courses using counting
glass constant of results found.
Conclusion
·
Fabric had perpendicular spreading
without stretching or crushing when test hence accurate outcomes found.
(ii) Wales per cm
Description
In
this practical test count how many Wales available in one centimeter.
Methodology
-
First knitted fabric was spread on table
without stretching.
-
Counting glass was kept on knitted
fabric.
-
Eye focused on counting glass lens.
-
Counting process was started using sharp
pointed needle or rod.
-
This counting process was done
lengthwise of fabric and repeated on five places.
-
Finally each result was recorded.
Calculations/
Recordings
Place
|
No. of Wales per 2cm
|
No. of Wales per 1cm
|
Wales per inch
|
1
|
28
|
14
|
35.56
|
2
|
27
|
13.5
|
34.29
|
3
|
27
|
13.5
|
34.29
|
4
|
28
|
14
|
35.56
|
5
|
27
|
13.5
|
34.29
|
Average
|
27.4
|
13.7/cm
|
34.798/inch
|
Here
each observation were taken using 2cm x 2cm
hence, finally 13.7 average was found but wales count should not decimal
points based hence wales per cm value is conclude as 14.
Observations
·
When counting wales using counting glass
two types of results found. (27 and 28)
Conclusion
·
Some places of knitted fabric may have
slightly stretch or pressed hence, conclude outcome may have changed due to
that reason.
(iii) Stitch density
Description
In
this practical test, hope to find how many density of stitches available in one
square centimeter.
Methodology
-
Multiplied provisory found courses per
centimeter and wales per centimeter.
Calculations/
Recordings
Stitch density (SD) = Course density x
Wales density
= (Course/cm) x (wales/cm)
= 18cm-1 x 14cm-1
= 252
cm-2
(iv) Stitch length
Description
Stitch length can be explained as theoretically the single length of yarn
which include one
needle loop and half of a sinker loop between that needle loop and the adjacent needle
loop.
needle loop and half of a sinker loop between that needle loop and the adjacent needle
loop.
Calculation
l2
=
stitch length
ks
= Dimensional constant (dry relaxed, wet relaxed or finished relax )
s = stitch
density (wales/cm x course/cm)
Formula,
s
= ks/ l2
It
can be written as,
l
= √ks/s
According
to this formula, previously calculated stitch density was applied with finished
relaxed estate.
l = √2360/252cm-2
= √9.36507
= 3.0602 mm
(v) Calculation the
knitted yarn length requirement to knit 5000m2 of fabric.
Description &
Calculation
To
find knitted yarn length requirement for 5000 m2 fabric we need to use previously found loop
length and that can be written as,
= loop length x stitch
density
= 3.0602
mm x
252cm-2
For 1 m2
fabric = 3.0602
x 10-6 x 252 x 104 km
= 7.71170
km
For
1000 m2 fabric = 7.71170
km x 1000
= 7711.704
km
For
5000 m2 fabric = 7711.704
km x 5000m2/1000m2
= 38558.52 km
